4m^2+8m=32

Solution for 4m^2+8m=32 equation:

4m^2+8m=32

We move all terms to the left:

4m^2+8m-(32)=0

a = 4; b = 8; c = -32;
Δ = b2-4ac
Δ = 82-4·4·(-32)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*4}=\frac{-32}{8}
=-4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*4}=\frac{16}{8}
=2
$